A) the probability of not getting doublet is \[\frac{5}{6}\]
B) the probability of getting a total of at least 10 is 1/6
C) the probability of not getting a total as a perfect square is 29/36
D) All of the above
Correct Answer: D
Solution :
| Two dice are thrown simultaneously |
| Total number of outcomes = 36 |
| Doublet = {(1, 1), (2, 2), (3, 3), (4, 4), (5,5), (6, 6)} |
| Total of atleast 10 = {(4, 6), (5, 5), (6, 4), (5, 6), (6, 5), (6, 6)} |
| Total is perfect square = {(1, 3), (2, 2), (3, 1), (3, 6), (4, 5), (5,4), (6, 3)} |
| [a] P (doublet) =6/36 =1/6, |
| P (not doublet) \[=1-\frac{1}{6}=\frac{5}{6}\] |
| [b] P (getting total of atleast 10) |
| =6/36=1/6 |
| [c] P (perfect square) =7/36, |
| P (not a perfect square) \[=1-\frac{7}{36}=\frac{29}{36}\] |
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