A) \[\frac{1}{9}\]
B) \[\frac{2}{9}\]
C) \[\frac{4}{9}\]
D) \[\frac{5}{9}\]
Correct Answer: A
Solution :
Total number of elementary outcomes = 36 Favourable outcomes are (4, 3), (3, 4), (6, 2), (2, 6) i.e. 4 in number. \[\therefore \]Required probability \[=\frac{4}{36}=\frac{1}{9}\]
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