A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{8}\]
D) \[\frac{1}{4}\]
Correct Answer: D
Solution :
Here, S = {(3,1), (2,2), (1,3), (6,2), (5,3), (4,4), (3,5), (2,6), (6,6)}. Total number of possible outcomes = 36 Number of favourable outcomes = 9 \[\therefore \]P (sum of two numbers will be multiple of 4) \[=\frac{4}{36}=\frac{1}{4}\]You need to login to perform this action.
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