A) \[\frac{1}{3}\]
B) \[\frac{1}{4}\]
C) \[\frac{2}{3}\]
D) \[\frac{1}{2}\]
Correct Answer: D
Solution :
Number of prime number (2, 3 and 5) = 3 Number of total outcomes = 6 \[P\left( E \right)=\frac{3}{6}=\frac{1}{2}\]
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