A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{3}\]
D) \[\frac{2}{3}\]
Correct Answer: B
Solution :
Total number of outcomes \[=\text{ }2\times 6\text{ }=\text{ }12\] Favourable outcomes are [T2, T3, T5] i.e. 3 in number. \[\therefore \] Required probability \[=\frac{3}{12}=\frac{1}{4}\]
You need to login to perform this action.
You will be redirected in
3 sec
