10th Class Mathematics Probability Question Bank MCQs - Probability

  • question_answer
    The probability that an ordinary year contains 53 Sundays is

    A) \[\frac{2}{7}\]

    B) \[\frac{1}{7}\]

    C) \[\frac{7}{53}\]

    D) \[\frac{7}{52}\]

    Correct Answer: B

    Solution :

    There are 365 days in an ordinary year. Number of full weeks in 365 days \[=52\left[ 365=7\times 52+1 \right]\] The remaining 1 day can be any one of the seven week days. Thus, the probability of this day to be Sunday \[=\frac{1}{7}\]


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