A) \[\frac{1}{183}\]
B) \[\frac{2}{365}\]
C) \[\frac{1}{365}\]
D) \[\frac{1}{366}\]
Correct Answer: D
Solution :
| [d] As 1996 was a leap year. so total number of days in the year \[1996=366\] |
| \[\therefore \] Total number of possible outcomes = 366 |
| Number of favourable outcomes that two friends have the same birth date = 1\[\therefore \] Required probability \[=\frac{1}{366}\] |
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