10th Class Mathematics Polynomials Question Bank MCQs - Polynomials

  • question_answer
    If   one   zero   of   the   quadratic   polynomial \[\text{2}{{\text{x}}^{2}}-\text{6kx}+\text{6x}-\text{7}\]is negative of the other, then k is equal to:

    A) \[-1\]

    B) \[1\]

    C) \[0\]

    D) \[-\frac{1}{2}\]

    Correct Answer: B

    Solution :

    [b] Let \[f(x)=2{{x}^{2}}-6kx+6x-7\]
    \[=2{{x}^{2}}-6(k-1)x-7\]
    Given, one zero of \[f(x)\] is negative of the other.
    \[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\alpha +(-\alpha )=-\left\{ \frac{-6(k-1)}{2} \right\}\]
    \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3(k-1)=0\Rightarrow \,\,k=1\]


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