A) linear
B) quadratic
C) cubic
D) None of these
Correct Answer: A
Solution :
[a] Given two of the zeroes of a cubic polynomial are zero. |
Let \[\alpha ,\beta \] and \[\gamma \] be the zeroes of a cubic polynomial |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\alpha =\beta =0\] |
Now, \[\alpha \beta \gamma =-\frac{\text{Constant term}~~}{\text{Coefficient of}\,\,{{x}^{2}}}=0\times \gamma =0\] |
\[\Rightarrow \] Constant term = 0 provided, coefficient of \[{{x}^{2}}\ne 0\]. |
So, cubic polynomial does not have linear. |
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