A) \[1\]
B) \[0\]
C) \[-1\]
D) \[\frac{1}{2}\]
Correct Answer: A
Solution :
[a] Given, \[a+b+c=0\] |
Let \[f(x)=a{{x}^{2}}+bx+c\] |
If \[x=1\] is a zero of \[f(x),\] |
Then \[f(1)=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,a{{(1)}^{2}}+b(1)+c=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,a+b+c=0\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0=0\] (which is true) |
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