A) \[\frac{4}{3}\]
B) \[\frac{-4}{3}\]
C) \[\frac{2}{3}\]
D) \[\frac{-2}{3}\]
Correct Answer: A
Solution :
| [a] Let \[p(x)=(k-1){{x}^{2}}+kx+1\] |
| Given that, one of the zeroes is \[-3,\]then |
| \[p(-3)=0\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(k-1)\,\,{{(-3)}^{2}}+k(-3)+1=0\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,9(k-1)-3k+1=0\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,6k-8=0\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,k=4/3\] |
You need to login to perform this action.
You will be redirected in
3 sec
