A) k=3
B) k=-3
C) \[k=\pm \,3\]
D) k=2
Correct Answer: C
Solution :
| Let \[\alpha \] and \[\beta \]are the zeroes of the polynomial |
| \[f\left( x \right)=4{{x}^{2}}-27x+3{{k}^{2}}\] |
| \[\alpha +\beta =\frac{27}{4},\,\alpha \,.\,\beta =\frac{3{{k}^{2}}}{4}\] |
| As sum of zeroes would be equal to product of zeroes |
| \[\alpha +\beta =\alpha \beta \] |
| \[\frac{27}{4}=\frac{3{{k}^{2}}}{4}\] |
| \[{{k}^{2}}=9\] |
| \[k=\pm 3\] |
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