A) \[-\frac{8}{7}\]
B) \[-\frac{3}{7}\]
C) \[\frac{2}{7}\]
D) \[\frac{6}{8}\]
Correct Answer: B
Solution :
| \[\alpha\]and \[\beta\]are the zeroes of \[4{{x}^{2}}+3x+7\] |
| \[\alpha +\beta =\frac{-\,Coefficient\text{ }of\text{ }x}{Coefficient\text{ }of\text{ }{{x}^{2}}}=-\frac{3}{4}\] |
| \[\alpha \,.\,\beta =\frac{Cons\tan t\,term}{Coefficient\,of\,{{x}^{2}}}=\frac{7}{4}\] |
| \[\frac{1}{\alpha }+\frac{1}{\beta }=\frac{\alpha +\beta }{\alpha \,.\,\beta }=\frac{-\frac{3}{4}}{\frac{7}{4}}=-\frac{3}{7}\] |
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