A) -3
B) -2
C) \[\pm \,\frac{4\sqrt{7}}{3}\]
D) None of these
Correct Answer: C
Solution :
| Given, p and q are the zeroes of quadratic equations |
| \[\therefore \,\,p+q=\frac{-2}{3}\] and \[pq=-3\] |
| \[\therefore \,\,\,p-q=\pm \sqrt{{{\left( p+q \right)}^{2}}-4pq}\] |
| \[=\pm \sqrt{{{\left( \frac{-2}{3} \right)}^{2}}-4\times \left( -3 \right)}=\pm \sqrt{\frac{4}{9}+12}=\pm \frac{4\sqrt{7}}{3}\] |
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