A) 21
B) 20
C) -21
D) 18
Correct Answer: C
Solution :
Given, 3 is a zero of polynomial \[2{{x}^{2}}+x+k\] |
Let \[f\left( x \right)=2{{x}^{2}}+x+k\] |
\[f\left( 3 \right)=0\] |
\[0=2{{\left( 3 \right)}^{2}}+3+k\] |
\[k\text{ }=-\left( 18\text{ }+3 \right)\] |
\[k=-21\] |
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