A) 1
B) 2
C) 3
D) more than 3
Correct Answer: D
Solution :
| The equation of a quadratic polynomial is \[{{x}^{2}}\]- (sum of zeroes) x + product of zeroes Sum of zeroes = - 2 + 5=3 and product of zeroes \[=-2\times 5=-10\] |
| \[\therefore\] Equation \[={{x}^{2}}-3x-10\] |
| . We know that, the zeroes do not change if the polynomial is divided or multiplied by a constant. |
| \[\therefore \,\,k{{x}^{2}}-3kx-10k\]will also have - 2 and 5 as their zeroes. As k can take any real value there can be many polynomial having - 2 and 5 as their zeroes |
You need to login to perform this action.
You will be redirected in
3 sec
