A) 0
B) 1
C) 2
D) None of these
Correct Answer: A
Solution :
| Given, \[5x+4y+6=0\] and \[10x+8y-12=0\] |
| On comparison with standard equation |
| \[{{a}_{1}}=5,\,{{b}_{1}}=4,\,{{c}_{1}}=6\] |
| \[{{a}_{2}}=10,\,{{b}_{2}}=8,\,{{c}_{2}}=-12\] |
| Here, \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\,\,\Rightarrow \frac{5}{10}=\frac{4}{8}\ne \frac{6}{-12}\] |
| These represents parallel lines so there is no any common solution |
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