A) \[-14/3\]
B) \[2/5\]
C) \[5\]
D) \[10\]
Correct Answer: D
Solution :
| [d] Given, \[x+2y=3\] and \[5x+ky+7=0\] |
| Here, \[{{a}_{1}}=1,\,{{b}_{1}}=2,\,{{c}_{1}}=3\] |
| and \[{{a}_{2}}=5,\,{{b}_{2}}=k,\,{{c}_{2}}=-7\] |
| Condition of inconsistency, |
| \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{5}=\frac{2}{k}\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,k=10\] |
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