A) \[x+y=8,\,\,\frac{x+1}{y}=\frac{1}{2}\]
B) \[x+y=8,\,\,\frac{x}{y}+1=\frac{1}{2}\]
C) \[\frac{x}{y}=8,\,\frac{x}{y+1}=\frac{1}{2}\]
D) \[x+y=8,\,\frac{x}{y+1}=\frac{1}{2}\]
Correct Answer: D
Solution :
[d] Let the numerator and denominator of the fraction be x and y respectively. |
According to the question, |
\[x+y=8\] |
and \[\frac{x}{y+1}=\frac{1}{2}\] |
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