A) True
B) False
C) Cannot say
D) Partially true/false
Correct Answer: A
Solution :
| Given, \[3x-y=3\] |
| \[9x\text{ }-\text{ }3y\text{ }=9\] |
| On comparison with the standard equation |
| \[{{a}_{1}}x+{{b}_{1}}y+{{c}_{1}}=0\] and \[{{a}_{2}}x+{{b}_{2}}y+{{c}_{2}}=0\] |
| \[{{a}_{1}}=3,\,{{b}_{1}}=-1,\,{{c}_{1}}=-3\] |
| \[{{a}_{2}}=9,\,{{b}_{2}}=-3,\,{{c}_{2}}=-9\] |
| Here |
| \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{3}{9}=\frac{{{b}_{1}}}{{{b}_{2}}}=\frac{-1}{-3}=\frac{{{c}_{1}}}{{{c}_{2}}}=\frac{-3}{-9}\] |
| So, the lines are coincident lines and hence infinite solution. |
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