A) \[-\frac{5}{4}\]
B) \[\frac{2}{5}\]
C) \[\frac{15}{4}\]
D) \[\frac{3}{2}\]
Correct Answer: C
Solution :
| [c] Given equations of lines are |
| \[3x+2ky-2=0\] |
| and \[2x+5y+1=0\] |
| Here, \[{{a}_{1}}=3,\,{{b}_{1}}=2k,\,{{c}_{1}}=-2\] |
| and \[{{a}_{2}}=2,\,{{b}_{2}}=5,\,{{c}_{2}}=1\] |
| Since, the given lines are parallel |
| \[\therefore \,\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\Rightarrow \frac{3}{2}=\frac{2k}{5}\Rightarrow k=\frac{15}{4}\] |
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