A) Rs 8 ; Rs 100
B) Rs 10, Rs 8
C) Rs 8 ; Rs 10
D) Rs 20, Rs 5
Correct Answer: C
Solution :
| Let fare from bus stand to Pitampura be Rs x and to Dilshad Garden be Rs y. According to the question, we have Cost of 2 tickets to Pitampura + 3 tickets to Dilshad Garden = Rs 46 and cost of 3 tickets to Pitampura + 5 tickets to Dilshad Garden = Rs 74 |
| \[\therefore \] We get |
| \[2x+\text{ }3y=46\] ...(i) |
| and \[3x+5y=74\] ...(ii) |
| Multiplying Eq. (i) by 3 and Eq. (ii) by 2, |
| we get |
| \[6x+9y=138\] ...(iii) |
| and \[6x+10y=148\] ...(iv) |
| Subtracting Eq. (iii) from Eq. (iv), we get |
| \[y=10\] |
| From Eq. (i), |
| \[2x+3\left( 10 \right)=46\] |
| \[\Rightarrow \,\,2x+30=46\] |
| \[\Rightarrow \,\,\,2x=16\] |
| \[\Rightarrow \,\,\,x=8\] |
| Hence, the fare from the bus stand in Delhi to Pitampura is Rs 8 and the fare to Dilshad Garden is Rs 10. |
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