A) \[2x+7y=11\]
B) \[4x-2y=5\]
C) \[x-3y=5\]
D) \[3x-4y=8\]
Correct Answer: A
Solution :
[a] Putting \[x=2,\] \[y=1\]in given equations, we-have |
[a] \[LHS=2(2)+7(1)=11=RHS\] |
[b] \[LHS=4(2)-2(1)=6\ne RHS\] |
[c] \[LHS=2-3(1)=-1\ne RHS\] |
[d] \[LHS=3(2)-4(1)=2\ne RHS\] |
Hence, \[x=2,\]\[y=1\] is a solution of the linear equation given in option [a]. |
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