A) \[k=8\]
B) \[k=\frac{-7}{8}\]
C) \[k=-56\]
D) \[k\ne -8\]
Correct Answer: A
Solution :
| [a] The given pair of linear equation is |
| \[x+2y-8=0\]and \[4x+ky+7=0.\] |
| Here, \[{{a}_{1}}=1,\,{{b}_{1}}=2,\,{{c}_{1}}=-8,\,{{a}_{2}}=4,\,{{b}_{2}}=k,{{c}_{2}}=7\] |
| Since, the system of equations have no solution |
| \[\therefore \,\,\,\,\,\,\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\,\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\,\,\frac{1}{4}=\frac{2}{k}\ne \frac{-8}{7}\] |
You need to login to perform this action.
You will be redirected in
3 sec
