A) 10
B) 7
C) 3
D) 12
Correct Answer: D
Solution :
[d] The given equations are \[x+3y-3=0\] and \[4x+ky+7=0.\]. |
Here, \[{{a}_{1}}=1,\,\,{{b}_{1}}=3,\,\,{{c}_{1}}=-3,\,\,{{a}_{2}}=4,\,\,{{b}_{2}}=k,\,\,{{c}_{2}}=7\] |
The system of equations has no solution, if |
\[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{{{b}_{1}}}{{{b}_{2}}}\ne \frac{{{c}_{1}}}{{{c}_{2}}}\Rightarrow \frac{1}{4}=\frac{3}{k}\Rightarrow k=12\] |
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