A) True
B) False
C) Can't say
D) Partially true/false
Correct Answer: A
Solution :
Given that, x, y and \[40{}^\circ \]are the angles of a triangle. |
\[\therefore \,\,\,\,\,x+y+40{}^\circ =180{}^\circ \] |
[since, the sum of all the angles of a triangle is \[180{}^\circ \]] |
\[\Rightarrow \,\,\,\,x+y=140{}^\circ \] (i) |
Also, \[x-y=30{}^\circ \] (ii) |
On adding Eqs. (i) and (ii), we get |
\[2x=170{}^\circ \] |
\[\Rightarrow \,\,\,x=85{}^\circ \] |
On putting \[x\text{ }=\text{ }85{}^\circ \]in Eq. (i), we get |
\[85{}^\circ +y=140{}^\circ \] |
\[\Rightarrow \,\,\,\,\,\,\,\,y=55{}^\circ \] |
Hence, the required values of x and y are \[85{}^\circ \]and \[55{}^\circ \], respectively. |
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