A) 3
B) 4
C) 5
D) 6
Correct Answer: C
Solution :
| Given,\[2x\text{ }+\text{ }3y\text{ }=\text{ }5\] ... (i) |
| \[3x+2y=10\] ...(ii) |
| Multiply Eq. (i) by 3 and Eq. (ii) by 2, |
| we get |
| \[6x+9y=15\] |
| \[\underset{\underline{-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-\,\,\,}}{\mathop{6x+4y=20}}\,\] |
| \[9y=-5\] |
| \[y=-1\] |
| Substitute \[y=-1\] in Eq. (i), we get |
| \[2x\text{ }+\text{ }3\left( -1 \right)\text{ }=\text{ }5\] |
| \[2x\text{ }=\text{ }5\text{ }+\text{ }3\] |
| \[2x=8\] |
| \[x=4\] |
| \[\therefore \,\,x-y=4-\left( -1 \right)=5\] |
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