A) \[2x+3y-17=0\]
B) \[3x+2y-17=0\]
C) \[2x-3y+17=0\]
D) \[2x+3y+17=0\]
Correct Answer: B
Solution :
[b] |
[a] \[LHS=2(3)+3(4)-17=1\ne RHS\] |
[b] \[LHS=3(3)+2(4)-17=0=RHS\] |
[c] \[LHS=2(3)-3(4)+17=11\ne RHS\] |
[d] \[LHS=2(3)+3(4)+17=35\ne RHS\] |
\[\therefore \,\,x=3,\,\,y=4\] is the solution of the equation \[3x+2y-17=0.\] |
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