A) 48, 20
B) 40, 28
C) 40, 48
D) 20, 24
Correct Answer: C
Solution :
Let the two numbers be x and y. |
Then, by first condition, ratio of these two numbers = 5 : 6 |
\[x:y\,=5\,:\,6\] |
\[\Rightarrow \,\,\,\,\frac{x}{y}=\frac{5}{6}\,\,\Rightarrow y=\frac{6x}{5}\] |
and by second condition, then, 8 is subtracted from each of the numbers, then ratio becomes 4:5. |
\[\frac{x-8}{y-8}=\frac{4}{5}\] |
\[\Rightarrow \,\,\,\,5x-40=4y-32\] |
\[\Rightarrow \,\,\,5x-4y=8\] (ii) |
Now, put the value of y in Eq. (ii), we get |
\[5x-4\left( \frac{6x}{5} \right)=8\] |
\[\Rightarrow \,\,\,25x-24x=40\] |
\[\Rightarrow \,\,x=40\] |
Put the value of x in Eq. (i), we get |
\[y=\frac{6}{5}\times 40\] |
\[=6\times 8=48\] |
Hence, the required numbers are 40 and 48. |
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