A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[-\frac{1}{2}\]
D) \[-\frac{1}{3}\]
Correct Answer: B
Solution :
[b] Since, \[(3,a)\] lies on the line \[2x-3y=5\] |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,2(3)-3(a)=5\] |
\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,6-3a=5\Rightarrow 3a=1\,\,\,\,\,\,\,\,\Rightarrow \,\,\,a=\frac{1}{3}\] |
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