A) The electron will be accelerated along the axis.
B) The electron path will be circular about the axis.
C) The electron will experience a force at \[{{45}^{\operatorname{o}}}\] to the axis and hence execute a helical path.
D) The electron will continue to move with uniform velocity along the axis of the solenoid.
Correct Answer: D
Solution :
Option [d] is correct Explanation: The magnetic field inside the long current carrying solenoid is uniform. Therefore, magnitude of force on the electron of charge (- e) is given by F = - evB sin\[\theta \] = 0 (\[\theta \] = \[{{0}^{\operatorname{o}}}\]) as magnetic field and velocity are parallel. The electron will continue to move with uniform velocity along the axis of the solenoid.
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