12th Class Physics Magnetism Question Bank MCQs - Moving Charges and Magnetism

  • question_answer
    A current carrying circular loop of radius R is placed in the x - y plane with centre at the origin. Half of the loop with x > 0 is now bent so that it now lies in the y - z plane.

    A) The magnitude of magnetic moment now diminishes.

    B) The magnetic moment does not change.

    C) The magnitude of B at (0.0.z), z >>R increases.

    D) The magnitude of B at (0.0.z), z >>R is unchanged.

    Correct Answer: A

    Solution :

    Option [a] is correct.
    Explanation: For a circular loop of radius R, carrying current J in x-y plane, the magnetic moment M =\[\operatorname{I}\ \times \pi {{\operatorname{R}}_{2}}\].
    It acts perpendicular to the loop along z-direction.
    When half of the current loop is bent in y-z plane, then magnetic moment due to half current loop is x-y plane, \[{{\operatorname{M}}_{2}}=\operatorname{I}(\pi {{R}_{2}}/2)\]acting along z-direction.
    Magnetic moment due to half current loop in y-z plane, \[{{\operatorname{M}}_{2}}=\operatorname{I}(\pi {{R}_{2}}/2)\]along x-direction.
    Net magnetic moment due to entire bent current loop,
           \[{{\operatorname{M}}_{net}}=\sqrt{M_{1}^{2}+M_{2}^{2}}\]
        =  \[\sqrt{2}\frac{\operatorname{I}\pi {{\operatorname{R}}^{2}}}{2}\]
           = \[\frac{\operatorname{M}}{\sqrt{2}}\]
    Therefore, \[{{\operatorname{M}}_{net}}\]< M or M diminishes.


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