12th Class Physics Magnetism Question Bank MCQs - Moving Charges and Magnetism

  • question_answer
    To convert a galvanometer to ammeter a shunt S is to be connected with the galvanometer. The effective resistance of the ammeter then is

    A) GS/(G+S)

    B) (G+S)/GS

    C) G+S

    D) None of the above

    Correct Answer: A

    Solution :

    Option [a] is correct. Explanation: Shunt (S) is connected m parallel to the galvanometer (resistance G). So, the effective resistance is GS/(G+S). 


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