| An infinitely long straight conductor is bent into the shape as shown in the figure. Current in it is i and the radius of the circular loop is r. The magnetic field at its centre is |
 |
A) Zero
B) Infinite
C) \[\frac{{{\mu }_{0}}i}{2\pi r}(\pi -1)\]
D) \[\frac{{{\mu }_{0}}i}{2\pi r}(\pi +1)\]
Correct Answer: C
Solution :
| Option [c] is correct. |
| Explanation: Magnetic field at O due to ABCD straight conductor = \[\frac{{{\mu }_{0}}i}{2\pi r}\] |
| Magnetic field at O due to the BEC circular conductor = \[\frac{{{\mu }_{0}}i}{2r}\] |
| The fields are in opposite direction. Hence the resultant field at O is \[\frac{{{\mu }_{0}}i}{2r}\] - \[\frac{{{\mu }_{0}}i}{2\pi r}\]=\[\frac{{{\mu }_{0}}i}{2\pi r}(\pi -1)\] |
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