A) BLH cos\[\theta \]
B) \[BL\text{ }cos\theta \times {{(2gH)}^{1/2}}\]
C) \[BL\text{ }cos\theta /{{(2gH)}^{1/2}}\]
D) None of the above
Correct Answer: B
Solution :
Option [b] is correct. Explanation: Horizontal component of magnetic field = \[B\,\,\,cos\theta \] Velocity of the rod = \[{{(2gH)}^{1/2}}\] Induced e.m.f. = \[BLv\text{ }=BL\text{ }cos\theta \times {{(2gH)}^{1/2}}\]
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