A) \[\operatorname{B}={{B}_{v}}\times {{B}_{H}}\]
B) \[\operatorname{B}={{B}_{v}}/{{B}_{H}}\]
C) \[\operatorname{B}={{B}_{v}}+{{B}_{H}}\]
D) \[\operatorname{B}=\sqrt{\operatorname{B}_{\operatorname{V}}^{2}+B_{H}^{2}}\]
Correct Answer: D
Solution :
| Option (d) is correct |
| Explanation: B = B cos\[\theta \] |
| \[{{\operatorname{B}}_{V}}=Bsin\delta \] |
| \[\therefore \] \[\operatorname{B}=\sqrt{\operatorname{B}_{\operatorname{V}}^{2}+B_{H}^{2}}\] |
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