A) \[\sin \theta \]
B) \[\sec \theta \]
C) \[\cos \theta \]
D) \[\text{cosec}\theta \]
Correct Answer: C
Solution :
| [c] \[\frac{x}{\sqrt{{{a}^{2}}+{{x}^{2}}}}=\frac{x}{x\sqrt{{{\left( \frac{a}{x} \right)}^{2}}+1}}=\frac{1}{\sqrt{{{\left( \frac{a}{x} \right)}^{2}}+1}}.\] \[\left( \tan \theta =\frac{a}{x} \right)\] |
| \[\frac{1}{\sqrt{{{\tan }^{2}}\theta +1}}=\frac{1}{\sqrt{{{\sec }^{2}}\theta }}=\frac{1}{\sec \theta }=\cos \theta \] \[({{\tan }^{2}}\theta +1={{\sec }^{2}}\theta )\] |
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