A) True
B) False
C) Cannot say
D) Partially True/False
Correct Answer: B
Solution :
(False) Let us take \[A=30{}^\circ \] and \[B=60{}^\circ \] then LHS = \[\sin \,\left( 30{}^\circ +60{}^\circ \right)=\sin 90{}^\circ =1\] RHS \[=\sin 30{}^\circ +\sin 60{}^\circ \] \[=\frac{1}{2}+\frac{\sqrt{3}}{2}=\frac{1+\sqrt{3}}{2}\] \[LHS\ne RHS\]
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