A) 0
B) 1
C) -1
D) 2
Correct Answer: B
Solution :
Given, \[\cos A+{{\cos }^{2}}A=1\] \[\Rightarrow \,\,\,\,\cos A=1-{{\cos }^{2}}A\] \[\Rightarrow \,\,\,\cos A={{\sin }^{2}}A\] \[\left[ \because \,1-{{\cos }^{2}}A={{\sin }^{2}}A \right]\] (i) We have to find the value of \[{{\sin }^{2}}A+{{\sin }^{4}}A\] \[\Rightarrow \,\,{{\sin }^{2}}A+{{\sin }^{4}}A\] \[\Rightarrow \,\,\cos A+{{\cos }^{2}}A\] [from Eq (i)] \[\Rightarrow \,\,1\]You need to login to perform this action.
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