A) \[tan90{}^\circ \]
B) 1
C) \[sin45{}^\circ \]
D) 0
Correct Answer: D
Solution :
Given, \[\frac{1-{{\tan }^{2}}45{}^\circ }{1+{{\tan }^{2}}45{}^\circ }\] \[\frac{1-{{\left( 1 \right)}^{2}}}{1+{{\left( 1 \right)}^{2}}}=\frac{0}{2}=0\] \[\left[ \because \,\,\tan \,45{}^\circ =1 \right]\]You need to login to perform this action.
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