10th Class Mathematics Introduction to Trigonometry Question Bank MCQs - Introduction to Trigonometry

  • question_answer
    The value of \[\frac{1-{{\tan }^{2}}45{}^\circ }{1+{{\tan }^{2}}45{}^\circ }\] is

    A) \[tan90{}^\circ \]

    B) 1

    C) \[sin45{}^\circ \]

    D) 0

    Correct Answer: D

    Solution :

    Given, \[\frac{1-{{\tan }^{2}}45{}^\circ }{1+{{\tan }^{2}}45{}^\circ }\] \[\frac{1-{{\left( 1 \right)}^{2}}}{1+{{\left( 1 \right)}^{2}}}=\frac{0}{2}=0\] \[\left[ \because \,\,\tan \,45{}^\circ =1 \right]\]


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