A) 3/5
B) 3/4
C) 4/3
D) 5/3
Correct Answer: B
Solution :
Given, |
\[\cos A=\frac{4}{5}\] |
\[\therefore\] Let \[AB=4k\] and \[AC=5k\] |
Apply Pythagoras Theorem |
\[A{{B}^{2}}+B{{C}^{2}}=A{{C}^{2}}\] |
\[BC=\sqrt{25{{k}^{2}}-16{{k}^{2}}}=3k\] |
Now, \[\tan A=\frac{BC}{AB}=\frac{3k}{4k}=\frac{3}{4}\] |
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