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10th Class Mathematics Introduction to Trigonometry Question Bank MCQs - Introduction to Trigonometry

  • question_answer
    Is \[{{\tan }^{2}}30{}^\circ +{{\cot }^{2}}30{}^\circ =\frac{10}{3}?\]

    A) True

    B) False

    C) Cannot say

    D) Partially True/False

    Correct Answer: A

    Solution :

    (True) We know that, \[\tan \,30{}^\circ =\frac{1}{\sqrt{3}}\] and \[\cot \,30=\sqrt{3}\] We have, \[{{\tan }^{2}}30{}^\circ +{{\cot }^{2}}30{}^\circ \] \[={{\left( \frac{1}{\sqrt{3}} \right)}^{2}}+{{\left( \sqrt{3} \right)}^{2}}=\frac{1}{3}+3=\frac{1+9}{3}=\frac{10}{3}\]


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