An alkyl halide with molecular formula \[{{C}_{6}}{{H}_{13}}Br\] on dehydrohalogenation gives two isomeric alkenes X and Y with molecular formula \[{{C}_{6}}{{H}_{12}}\]. On reductive ozonolysis X and Y gave four compounds \[C{{H}_{3}}COC{{H}_{3}}\], \[C{{H}_{3}}CHO\], \[C{{H}_{3}}C{{H}_{2}}CHO\] and \[{{\left( C{{H}_{3}} \right)}_{2}}CHCHO\]. The alkyl halide is |
A) 4-bromo-2-methylpentane
B) 3-bromo-2-methylpentane
C) 2-bromo-2, 3-dimethylbutane
D) 2, 2-dimethyl-1-bromobutane.
Correct Answer: B
Solution :
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