A) \[{{C}_{2}}{{H}_{5}}Br+KN{{O}_{2}}\to {{C}_{2}}{{H}_{5}}-O-N=O+KBr\]
B)
\[{{C}_{2}}{{H}_{5}}Br+AgN{{O}_{2}}\to {{C}_{2}}{{H}_{5}}-\]
+AgBr
C) \[{{C}_{2}}{{H}_{5}}Br+AgCN\to {{C}_{2}}{{H}_{5}}NC+AgBr\]
D) \[{{C}_{2}}{{H}_{5}}Br+KCN\to {{C}_{2}}{{H}_{5}}NC+KBr\]
Correct Answer: D
Solution :
\[{{C}_{2}}{{H}_{5}}Br+KCN\to {{C}_{2}}{{H}_{5}}CN+KBr\] Due to ionic nature, the attack by CN- occurs through C atom and alkyl cyanide is formed.
You need to login to perform this action.
You will be redirected in
3 sec
