| In the circuit shown in Figure, initially key \[{{k}_{1}}\] is closed and key \[{{k}_{2}}\] is open. Then \[{{k}_{1}}\] is opened and \[{{k}_{2}}\] is closed. Then |
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A) Voltage across \[{{\operatorname{C}}_{1}}\] = Voltage across \[{{\operatorname{C}}_{2}}\]
B) Voltage across \[{{\operatorname{C}}_{1}}\]> Voltage across \[{{\operatorname{C}}_{2}}\] , if \[{{\operatorname{C}}_{1}}>{{\operatorname{C}}_{2}}\]
C) Charge on \[{{\operatorname{C}}_{1}}\] = charge on \[{{\operatorname{C}}_{2}}\]
D) None of the above
Correct Answer: A
Solution :
Option [a] is correct. Explanation: Since \[{{\operatorname{C}}_{1}}\] and \[{{\operatorname{C}}_{2}}\] are in parallel, Voltage across \[{{\operatorname{C}}_{1}}\] = Voltage across \[{{\operatorname{C}}_{2}}\]
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