A) Visible region
B) Infrared region
C) Ultraviolet region
D) Microwave region
Correct Answer: C
Solution :
Option [c] is correct. |
Explanation: \[\operatorname{E}=11\ eV=11\times 1.6\times 1{{0}^{-19}}J\] |
\[h=6.62\times {{10}^{-34}}Js\] \[E=hv\] |
\[\operatorname{v}=\frac{E}{h}=\frac{11\times 1.6\times {{10}^{-19}}}{6.62\times {{10}^{-34}}}=\frac{8.8\times {{10}^{-19+34}}}{3.31}\] |
=\[\frac{800}{331}\times {{10}^{15}}\operatorname{Hz}=2.65\times {{10}^{15}}\operatorname{Hz}\] |
This frequency radiation belongs to the ultraviolet region. |
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