A) 5 H
B) 1 H
C) 5\[\times {{10}^{-3}}\operatorname{H}\]
D) 5\[\times {{10}^{3}}\operatorname{H}\]
Correct Answer: C
Solution :
Option [c] is correct. |
Explanation: =\[-L\frac{di}{dt}\] |
\[5=-L\times \frac{0-1}{{{10}^{-3}}}\] |
\[\operatorname{L}=5\times 1{{0}^{-3}}H\] |
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