question_answer

A straight line is drawn joining the points \[(3,4)\] and \[(5,6)\]. If the Line is extended, the ordinate of the point on the line, whose abscissa is \[-1\] is:

A) \[-1\]

B) \[0\]

C) \[1\]

D) \[2\]

Correct Answer: B

Solution :

[b]

Let line is extended to \[C(-1,y)\] such that

\[AB:BC=k:1\]

\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{(-1)\times k+3}{k+1}=5\]

\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,k=-\frac{1}{3}\]

\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y=0\]