| In figure \[P(5,-3)\] and \[Q(3,y)\] are the points of Insertion of the line segment joining \[A(7,-2)\] and \[B(1,-5),\] then y equals: (CBSE 2012) |
|
A) \[2\]
B) \[4\]
C) \[-4\]
D) \[-\frac{5}{2}\]
Correct Answer: C
Solution :
[c] |
| \[AP=PQ=BQ\] |
| \[\Rightarrow \] Q is mid-point of PB |
| \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y=\frac{-3+(-5)}{2}=-4\] |
You need to login to perform this action.
You will be redirected in
3 sec
