10th Class Mathematics Coordinate Geometry Question Bank MCQs - Coordinate Geometry

  • question_answer
    The coordinates of the point equidistant from the vertices \[O(0,0),\] \[A(6,0)\] and \[B(0,8)\] of \[\Delta AOB\] are:

    A) \[(2,3)\]

    B) \[(3,4)\]

    C) \[(-3,4)\]

    D) \[(2,-3)\]

    Correct Answer: B

    Solution :

    [b]\[OA=\sqrt{{{(6-0)}^{2}}+{{(0-0)}^{2}}}=6\] units
    \[OB=\sqrt{{{(0-0)}^{2}}+{{(8-0)}^{2}}}=8\] units
    and\[AB=\sqrt{{{(0-6)}^{2}}+{{(8-0)}^{2}}}\sqrt{36+64}\]
    \[=\sqrt{100}=10\] units
    \[A{{B}^{2}}=O{{A}^{2}}+O{{B}^{2}}\]
    \[\therefore \,\,\Delta AOB\]is a right angle.
    So, mid-point of hypotenuse of \[\Delta AOB\] is the point which is equidistant from the given vertices.
    \[\therefore \] Required point \[=\left\{ \frac{6+0}{2},\frac{0+8}{2} \right\}\,\,=(3,4)\]


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